Team-BHP - View Single Post - The H bridge concept & Building an amplifier

amit1101 · 22nd December 2005, 21:11

hello naven

here is a small derivation which says that i will get 4 times output that is 400watts instead of just double that is 200wats
POWER = VOLTAGE*VOLAGE/RESISTANCE
P=V*V/R
In the h bridge configration the voltage is doubled across speaker ( basic concept of h bridge)
power is proportional to square of voltage so when voltage is doubled due to h bridge the power will increase by a factor of square of 2, that means 4

can any one tell if i am right

22nd December 2005, 21:11	#4 (permalink)
amit1101 BHPian Join Date: Dec 2005 Location: faridabad Posts: 76	hello naven here is a small derivation which says that i will get 4 times output that is 400watts instead of just double that is 200wats POWER = VOLTAGEVOLAGE/RESISTANCE P=VV/R In the h bridge configration the voltage is doubled across speaker ( basic concept of h bridge) power is proportional to square of voltage so when voltage is doubled due to h bridge the power will increase by a factor of square of 2, that means 4 can any one tell if i am right