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| | #1 (permalink) |
| BHPian | hi team bhp If i have an amplifier of 100watt rms into 2 channels can any one tell me what will be the output in watt rms if i connect these 2 channels in B bridge configration. will it become 2 times(200rms) or 4 times(400rms) ny help will be greatful thankz |
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| | #4 (permalink) |
| BHPian | hello naven here is a small derivation which says that i will get 4 times output that is 400watts instead of just double that is 200wats POWER = VOLTAGE*VOLAGE/RESISTANCE P=V*V/R In the h bridge configration the voltage is doubled across speaker ( basic concept of h bridge) power is proportional to square of voltage so when voltage is doubled due to h bridge the power will increase by a factor of square of 2, that means 4 can any one tell if i am right |
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| | #5 (permalink) | |
| Distinguished - BHPian ![]() | Quote:
with roughtly translate into 175WX1 @ 4ohms
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| | #6 (permalink) | |
| Team-BHP Moderator ![]() Join Date: Mar 2004 Location: mumbai
Posts: 11,789
| Quote:
P is also = I*I*R. that is where typical amps trip up. current capacity. Sam, my home brew 200W/ch 8 ohms home amp dumped over 500W in bridged mode into 8 ohms. Then again it has a 1200VA trany and 120,000uf of filter caps. The fact is I use about 10W of this 30kg beast. the rest is for show! | |
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| | #7 (permalink) |
| BHPian | Well let me have the best of it... So guys, can someone tell me if i can bridge a 4 channel amp which is manufactured by the company to run 4 channel and 2 channels to do 1 channel. IE, Connect on single sub and derive the complete power to a sub. Well I am sure u can have two speaker setup on these easily but is the 1 channel setup advisable and recommended. If yes, how is it done. Hope i am clear.
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| | #8 (permalink) | |
| Distinguished - BHPian ![]() | Quote:
Hello General, To tell you the truth - NO you arent clear ![]() But i gather you want to bridge 4 channels into 1. No amplifier i know of does that yet.
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| | #9 (permalink) | |
| BHPian | Quote:
here is the derivation in i square r format suppose u have a normal amp , its a push pull amp and operates at +/- V rms volts impedance of u r speaker be R ohms during positive cycle the currrent through speaker is +V/R rms during negative cycle the currrent through speaker is -V/R rms total power is I*I*R where I= V/R rms V*V/R watts ...........................................(1) now u make an H bridge since the voltage across speaker is now doubled the current will aslo double bcoz V=I*R thus in bridge current during positive cycle is +2V/R current during negative cycle is -2V/R now power by I*I*R (2V)(2v)/R 4*V*V/R watts ...........................................(2) now the power in equation 2(bridge) is 4 times that of equation 1(normal) amit
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| | #10 (permalink) |
| Distinguished - BHPian ![]() | amit101 - look at navins statement again: CURRENT CAPACITY is the key. We're talking about amplifiers that run off a 12V battery and have a limited power supply to say the least. Current will double only if the power supply is capable enough to supply the juice
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| | #11 (permalink) | |
| BHPian | Quote:
I am sorry.. If i were in ur place reading my post, I would be shellin u with abuse... heheheh!!! U answered my question... but i tried reading my own post and it doesnt make any sense at all. U must be a genius to understand what i was looking for... ![]()
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| | #13 (permalink) | |
| BHPian | Quote:
__________________ Funniest thing about this particular signature is that by the time you realise it doesnt say anythin its 2 late to stop reading it | |
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| | #14 (permalink) | |
| BHPian | Quote:
we use a circuit called chopper boost up circuit which can avail us 250 volts dc very easily u must have noticed coils in amp. those are passive filters but mainly they are the paart of this chopper ckt. if there was no choppers we would have to keep big big transofrmers at our back with amp. :-)
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Last edited by amit1101 : 25th December 2005 at 17:59. | |
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| | #15 (permalink) |
| Team-BHP Moderator ![]() Join Date: Mar 2004 Location: mumbai
Posts: 11,789
| there is a limit on the power supply on most power amps. P=V*I=I*I*R Even is V=250 you still have to dump amps. it is the current capacity which limits most amps. Last edited by navin : 25th December 2005 at 20:57. |
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