[Indian2003]

This is the Lanz Bulldog from the early 50s. This tractor has a massive single cylinder 10,300 cc engine. This is a 2-stroke diesel producing the maximum 45 HP at 630 RPM.

The engine can rotate both ways and for reverse you just change the rotation of the engine. The engine is not stopped for the change in rotation.

The Lanz company was taken over by John Deere and the name is not used anymore.

https://www.youtube.com/watch?v=zKsBUDPcI6A

https://en.wikipedia.org/wiki/Lanz_Bulldog

[RedTerrano]

Originally Posted by Indian2003

This tractor has a massive single cylinder 10,300 cc engine. This is a 2-stroke diesel producing the maximum 45 HP at 630 RPM.

Only 45 HP for a 10,300 cc engine?!

A quick google gave me this about the Ashok Leyland 2516 IL

Powered by an H Series Turbocharged Intercooled engine with Inline FIP 5,660 cc diesel motor, Ashok Leyland 2516 IL belts out 160 bhp power and 550 Nm torque.

So 10,300 cc = 45 HP, but
5,600 cc = 160 bhp?

Can someone please explain how power is not proportional to the CC? I suspect somehow bore and stroke come into the picture but when it comes to such things I am a total noob.

Also, are HP, BHP, PS the same thing?

[abhishek46]

Originally Posted by RedTerrano

Only 45 HP for a 10,300 cc engine?!

A quick google gave me this about the Ashok Leyland 2516 IL


So 10,300 cc = 45 HP, but
5,600 cc = 160 bhp?

Can someone please explain how power is not proportional to the CC? I suspect somehow bore and stroke come into the picture but when it comes to such things I am a total noob.

Also, are HP, BHP, PS the same thing?

Power is not proportional to Cubic Capacity. (CC).
The power rating of an engine depends on the Compression Ratio, the amount of fuel that can be combusted cleanly, and maximum speed(rpm) that the engine can spin to.

Old Engines have very low compression, and very low RPM limit.
That's why they produce lesser power per CC.

To understand the difference between HP, BHP & PS, pls have a look at the below.

https://youtu.be/dIDUlRqay3E

[RadixLecti]

Originally Posted by RedTerrano

Can someone please explain how power is not proportional to the CC? I suspect somehow bore and stroke come into the picture but when it comes to such things I am a total noob.

Power is proportional to swept volume (or cubic capacity), all else being equal.

If you want some maths, then power produced by one cylinder = PLAN, where

P = Mean effective pressure (link) of that cylinder. This is affected by peak pressure, compression pressure, fuel quantity, injection/ignition timing, valve timing, charge air pressure and temperature, compression ratio, engine speed etc etc

L = Stroke length

A = Area of cylinder bore

N = Number of power strokes per second

So if you managed to hold P and N constant, then yes, power would increase proportionally with L x A, which is swept volume (cc). This can be seen clearly in industrial engines which can be purchased in a wide range of cylinder configurations, with each cylinder producing an identical amount of power. So a 12 cylinder engine will produce almost exactly double the power of a 6 cylinder engine of the same type in the same state of tune, because the total swept volume is doubled.