How many 176 Ω resistors (in parallel) are required to carry 5 A on a 220 *V* line?

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#### Solution

For *x* number of resistors of resistance 176 Ω, the equivalent resistance of the resistors connected in parallel is given by Ohm’s law as*V*= *IR**R*= *V*/*I*

Where,

Supply voltage, *V*= 220 *V*

Current, *I* = 5 A

Equivalent resistance of the combination = *R*,given as

`1/R=x xx(1/176)`

`R=176/x`

From Ohm's law

`V/I=176/x`

`x=(176xxI)/V=(176xx5)/220=4`

Therefore, four resistors of 176 Ω are required to draw the given amount of current.

Concept: System of Resistors - Resistances in Parallel

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